例題1：
Choose the three valid identifiers from those listed below.
A. IDoLikeTheLongNameClass
B. $byte
C. const
D. _ok
E. 3_case
解答：A, B, D
點評：Java中的標示符必須是字母、美元符($)或下劃線(_)開頭。關鍵字與保留字不能作為標示符。選項C中的const是Java的保留字，所以不能作標示符。選項E中的3_case以數字開頭，違反了Java的規則。
例題2：
How can you force garbage collection of an object?
A. Garbage collection cannot be forced
B. Call System.gc().
C. Call System.gc(), passing in a reference to the object to be garbage collected.
D. Call Runtime.gc().
E. Set all references to the object to new values（null, for example）.
解答：A
點評：在Java中垃圾收集是不能被強迫立即執行的。調用System.gc()或Runtime.gc()靜態方法不能保證垃圾收集器的立即執行，因為，也許存在著更高優先級的線程。所以選項B、D不正確。選項C的錯誤在于，System.gc()方法是不接受參數的。選項E中的方法可以使對象在下次垃圾收集器運行時被收集。
例題3：
Consider the following class:
1. class Test(int i) {
2. void test(int i) {
3. System.out.println(“I am an int.”);
4. }
5. void test(String s) {
6. System.out.println(“I am a string.”);
7. }
8.
9. public static void main(String args[]) {
10. Test t=new Test();
11. char ch=“y”;
12. t.test(ch);
13. }
14. }
Which of the statements below is true?(Choose one.)
A. Line 5 will not compile, because void methods cannot be overridden.
B. Line 12 will not compile, because there is no version of test() that rakes a char argument.
C. The code will compile but will throw an exception at line 12.
D. The code will compile and produce the following output: I am an int.
E. The code will compile and produce the following output: I am a String.
解答：D
點評：在第12行，16位長的char型變量ch在編譯時會自動轉化為一個32位長的int型，并在運行時傳給void test(int i)方法。
例題4：
Which of the following lines of code will compile without error？
A. int i=0;
if (i) {
System.out.println(“
Hi”);
}
B.
boolean b=true;
boolean b2=true;
if(b==b2) {
System.out.println(“So true”);
}
C.
int i=1;
int j=2;
if(i==1|| j==2)
System.out.println(“OK”);
D.
int i=1;
int j=2;
if (i==1 &| j==2)
System.out.println(“OK”);
解答：B, C
點評：選項A錯，因為if語句后需要一個boolean類型的表達式。邏輯操作有^、&、| 和 &&、||,但是“&|”是非法的，所以選項D不正確。
例題5：
Which two demonstrate a "has a" relationship? (Choose two)
A. public interface Person { }
public class Employee extends Person{ }
B. public interface Shape { }
public interface Rectandle extends Shape { }
C. public interface Colorable { }
public class Shape implements Colorable
{ }
D. public class Species{ }
public class Animal{private Species species;}
E. interface Component{ }
class Container implements Component{
private Component[] children;
}
解答：D, E
點評： 在Java中代碼重用有兩種可能的方式，即組合（“has a”關系）和繼承（“is a”關系）�！癶as a”關系是通過定義類的屬性的方式實現的；而“is a”關系是通過類繼承實現的。本例中選項A、B、C體現了“is a”關系；選項D、E體現了“has a”關系。
